(x^3)^3/2x^-4y^0

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Solution for (x^3)^3/2x^-4y^0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

y^0*x^-4*(((x^3)^3)/2) = 0

x^-4*(((x^3)^3)/2) = 0

1/2*x^5 = 0 // : 1/2

x^5 = 0

x = 0

x in { 0} 

x belongs to the empty set

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